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Mathematics 18 Online
OpenStudy (a1234):

What is the equation of this parabola?

OpenStudy (a1234):

OpenStudy (a1234):

I think it is y - 2 = 1/20(x - 4)^2, but I'm not sure.

OpenStudy (camper4834):

do you still need help?

OpenStudy (camper4834):

well idk what happened to you so i'll just give you my answer. I got 1/5(x-2)^2+1

OpenStudy (a1234):

It seems like (4, 2) is the vertex in the graph. Your equation gives a vertex of (2, 1).

OpenStudy (anonymous):

y - k = a(x - h)^2 is the classic parabola, although the simple Y=(x^2) is actually not considered one, it is called a catenary curve and is proven with the same math that shows that 1+1=3 not 2. The difference is how a cable bends when suspended between 2 posts, it takes on a slight dip in the center but at the ends it is still straight

OpenStudy (a1234):

Okay. So how do I write the equation?

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