Question

What is the interquartile range (IQR) of the data?

Answer 1

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Answer 2

heres the picture for the question

Answer 3

So we'll start with what is the median of this data?

Answer 4

it is 29.5

Answer 5

hello are you still there

Answer 6

Sorry, helping others as well...okay so good...the median is indeed 29.5

Now what is the first quartile?

Answer 7

How :(

Answer 8

So we have some points

10, 12, 16, 20, 26, 29, | 30, 31, 32, 36, 38, 40

We know the median is right ^ there

So now, to find the "first quartile" it is basically asking what is the median of the left side
And the same to find the "third quartile" we want the median to the right of that as well

Answer 9

OOK I get it

Answer 10

So now, what is the first, and what is the third quartiles?

Answer 11

Q1 is 18 and Q3 is 34

Answer 12

So is the answer 16

Answer 13

Bam! lol there ya go!

Answer 14

YAY!!!!!!!!!!!

Answer 15

In her first five basketball games, Sarah scored 2, 5, 10, 15, and 18 points.

What is the mean absolute deviation for this set of scores?

Answer 16

I don't get what Mean Absolute Deviation means.

Answer 17

So for this...you first need to find the mean of this data...

Answer 18

the mean is 10

Answer 19

Good, now you need to take each data point...and subtract the mean from it

BUT, since this is "absolute" we need the absolute value here...so still take each number, subtract the mean from it...and if it ends up being negative...just make it positive

Answer 20

Once you have done that, add up all of those values

Answer 21

I got -8, -5, 0, 5, and 8

Answer 22

Right, those are the numbers minus the mean..

So we want the absolute value of each so we just have

\(\large 8 , 5 , 0 , 5 , 8\) right?

Adding all those up we get?

Answer 23

The first two numbers are negatives though

Answer 24

They are indeed, And if the question was asking for the "mean deviation" that is what we would use

However since this is the "mean ABSOLUTE deviation" we need the absolute values

\[\large |-n| = n\]

Answer 25

Its 0 right

Answer 26

No, we use the absolute values

Here, so when we take the absolute values of each number minus the mean

\[\large |x - \mu| \]

We have

\[\large |2 - 10| = 8\]
\[\large |5 - 10| = 5\]
\[\large |10 - 10| = 0\]
\[\large |15 - 10| = 5\]
\[\large |18 - 10| = 8\]

And we add those up

Answer 27

So do I just Make them into positive numbers?

Answer 28

Yes, because again, we are finding the "mean ABSOLUTE deviation" so we need to absolute values which means just make the negative numbers positive

Answer 29

so its 26 Right?

Answer 30

Right, that is our "absolute deviation" now we just need the mean

So we take that 26 and divide it by the # of data points...which is 5

So \(\large \frac{26}{5} = ?\)

Answer 31

Is it 5.2

Answer 32

Looks right to me!

Answer 33

YAY

Answer 34

bye THANKS A LOT!!!!

Answer 35

No problem!