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Given ln(x−5)+ln(x−6)=1, Solve for x
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quotient rule\[\large\rm ln y - ln x = \ln \frac{ x }{ y}\] subtraction to division product rule \[\large \rm ln x + \ln y = \ln ( x \times y )\] addition ----> multiplication power rule \[\large\rm ln x^y = y \ln x\]
which one you should apply ?
Well, what I have so far is: ln(x-5)(x-6) = ln e (x-5)(x-6) = e^1 x^2-11x+30 = e^1 then i'm stuck
I just replaced 1 with ln e thinking that it might be easier that way since ln e = 1 but yeah still stuck
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