Solve for x . x/3 = 3 1/4
@nonopro
well, 4.x/3=31 4x=31/3 x=31/3.1/4 x=31/12
@Mrs_Allison I think you have misread the question @tiff9702 is it \[\frac{ x }{ 3 }= 3\frac{ 1 }{ 4 }\]
Oh!!!! im sorry, ill do it again for you
@MrNood Yes it is
multiply both sides by 3 that will give you the answer immediately
x=9/4
x/3=3.1/4 4x/3=3 4x=9 x=9/4
@Mrs.Allison That is not correct
how so?
multiply 3 and 1 quarter by 3
@tiff9702 can you do this? multiply BOTH sides of the equation by 3 @Mrs.Allison Please leave the answer for asker to try
what i did its correct, im pretty sure. I´m a math teacher --´
Well - I assure you it is very wrong
@Mrs.Allison If oyu wan to do it your way (which is more complicated than mine) then first youmust convert the right side to improper fraction 13/4
\[\frac{ x }{ 3 } = 3* \frac{ 1 }{ 4 }\]\[\frac{ x }{3 }= \frac{ 3 }{ 4 }\]\[x = \frac{ 3 }{ 4 } * 3\]\[x = \frac{ 9 }{ 4 }\]
did your answer was the same as mine?
calm yourself down please. And yes, if you multiply one side of the equation by 3 you have to multiply the other one too
@Mateaus I'm afraid your answer isALSO wrong PLEASE just simply multiply BOTH sides by 3 x/3 *3 = x (3 and 1/4) * 3 =????
isn't the main expression \[\frac{ x }{ 3 } = 3 * \frac{ 1 }{ 4 }\]??
no - there is no multiply on the right side it is 3 and 1/4 = (13/4)
how did you get 13?
3 = 12/4 + 1/4 = 13/4
there is no a + which is why I assumed it was multiplication
but it is the normal way of writing a whole number and fraction
What? I'm confused, if the 3 is multiplying the 1/4 then my answer is correct, it is not, then I don't know what is that 3 suppose to mean, there's no signal
Then it is 3 multiplied by 1/4
@tiff9702 What is the sign between 3 and 1/4?
NO it's not!! Just SAY it "" three and a quarter" like "two and five eights" or "six and three sixteenths" it is \[3\frac{ 3 }{ 4}\]
sorry \[3\frac{ 1 }{ 4 }\]
so...
so \[\frac{ x }{ 3 } = \frac{ 13 }{ 4 }\] so \[x=\frac{ 39 }{ 4} = 9\frac{ 3 }{ 4 }\]
Well according to tiff there is not a sign so we can assume it is how MrNood is describing it.
There's no sign?
@tiff9702 I expect you have lost interest by now My answer above is correct as you confirmed my original post of your equation.
She just told me it looks the same as how MrNood is showing.
lol
Solving problems mhmm hmmm
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