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Mathematics 10 Online
OpenStudy (kidrah69):

@mathmate

OpenStudy (kidrah69):

OpenStudy (kidrah69):

This is kind of what im working on 34 and 35 are the problem ones >_<

OpenStudy (mathmate):

Yeah, they look difficult, but not really if you know - cross multiplication - FOIL - solution of linear or quadratic equation in one unknown. What you need to do is first cross multiply. For #34, you have (x-3)(x+6)=x*x use FOIL to expand both sides (if necessary) x^2-3x+6x-18 = x^2 Cancel x^2 3x-18=0 and you can solve for the rest.

OpenStudy (mathmate):

For #35, the steps are the same. But in the end, you need to solve a quadratic equation, either by factoring, or by the quadratic formula.

OpenStudy (kidrah69):

2x(9-x) 5(x+4) 18x-2x^2+5x+20 -2x^2+23x+20 this cant be right... :/

OpenStudy (kidrah69):

oh thats number 35 btw...

OpenStudy (mathmate):

Don't forget the equal sign. \(\large \frac{9-x}{x+4}=\frac{5}{2x}\) Cross multiply: 2x(9-x)= 5(x+4) Expand \(18x-2x^2=5x+20\) Transpose terms \(2x^2-13x+20=0\) I'll let you finish the rest using factoring of quadratic expressions.

OpenStudy (kidrah69):

|dw:1432174969609:dw|

OpenStudy (kidrah69):

|dw:1432175012449:dw|

OpenStudy (kidrah69):

(x-8)=0 (x-5)=0 x=8 x=5

OpenStudy (mathmate):

Excellent! Well done! :)

OpenStudy (kidrah69):

:) thanks you!

OpenStudy (mathmate):

You're welcome! :)

OpenStudy (kidrah69):

Think we can do one more? :) you can pick it :P it does not have to be from that page it can be made up :)

OpenStudy (mathmate):

try: (5x-8)/(x+1) = (3x-2)/(7-x)

OpenStudy (kidrah69):

\[\frac{ 5x-8 }{ x+1}=\frac{ 3x-2 }{ 7-x }\] (5x-8)(7-x)=(x+1)(3x-2) \[35x-5x^2-8~=~ 3x^2-2x+3x-2\] \[ -2x^2-6+36x\] divde all by -2 \[2(x^2+18x-3) \]

OpenStudy (kidrah69):

is it right so far?

OpenStudy (mathmate):

Not sure after all divided by -2!

OpenStudy (kidrah69):

Would it just be 2? :/

OpenStudy (mathmate):

(5x-8)(7-x)=(x+1)(3x-2) Use FOIL 35x-5x^2-56+8x = 3x^2-2x+3x-2 Move everything to the right: 3x^2+x-2-(43x-5x^2-56)=0 8x^2-42x+54=0 Can you solve the rest?

OpenStudy (kidrah69):

4x^2-21x-27 |dw:1432177982352:dw| i have no idea...

OpenStudy (mathmate):

It's 4x^2-21x+27, and that makes a big difference, because then both m and n are negative!|dw:1432178219561:dw|

OpenStudy (kidrah69):

I hate this! T_T there is no solution am i right? :)

OpenStudy (mathmate):

Since it is +108, the \(sum\) of m and n must be -21, and both m and n are negative (in order that the product be positive). So check: 4*27 sum=31 too big 6*18 sum = 24 too big 9*12 sum = 21 Good! So |dw:1432178706326:dw|

OpenStudy (kidrah69):

(4x^2-12x)(-9x+27) 4x(x-3) -9(x-3) (4x-9)(x-3)

OpenStudy (kidrah69):

please say its right! >_<

OpenStudy (mathmate):

Yes, it's correct!, so x=? or ?

OpenStudy (kidrah69):

x=3 x=9/4

OpenStudy (mathmate):

Excellent! both correct!

OpenStudy (mathmate):

:)

OpenStudy (kidrah69):

:) thanks :)

OpenStudy (mathmate):

You're welcome! :) I think you are getting the hang of it pretty well!

OpenStudy (kidrah69):

:)

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