An equation is shown below: 6(2x – 11) + 15 = 3x + 12 Part A: Write the steps you will use to solve the equation, and explain each step. (6 points) Part B: What value of x makes the equation true? (4 points)
Ok so do you know how to solve equations?
kind of
Ok show me what you know :)
Im just really stuck on this problem and i dont even know where to begin
Think of Order of operations :)
Scratch that >_< first distribute.
Well im guessing we have to start by solving whats inside the paraenthensis
oh never mid
You figured it out?
no i still need help :)
oh ok :) 1) Distribute
so im guessing we had 6 and 15 together?
add
no no no we want to MULTIPLY!! :D \[6(2x – 11) + 15 = 3x + 12 \] Think: \[6\times2x=?\] \[6\times-11=?\]
6 x -11 = -66 and the other one equals 12x
yes! :D now we have.... \[12x-66+15=3x+12\] Combine like terms :) -66+15=?
-51
good \[12x−51=3x+12\] now combine like terms! (this is the fun part!) 12-3=? 12+51=?
ok so it woud euqual 9x= -39
nooo.... 12+51=?
63
good what is 63/9?
7
1 )Expand 12x−66+15=3x+12 2 )Simplify 12x−66+15 to 12x−51 12x−51=3x+12 3 )Add 51 to both sides 12x=3x+12+51 4 )Simplify 3x+12+51 to 3x+63 12x=3x+63 5) Subtract 3x from both sides 12x−3x=63 6) Simplify 12x−3x to 9x 9x=63 7 )Divide both sides by 9 x=639 8) Simplify 63/9 to 7 x=7
That answers part A and part B also good job! :D
Thank you so much!
No problem! Also welcome to openstudy!! :D
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