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Mathematics 19 Online
OpenStudy (anonymous):

May i get some help with an Equation

OpenStudy (anonymous):

OpenStudy (anonymous):

Steps that you have to follow to solve for \(\sf b_1\) 1. Multiply both sides by 2 and simplify. 2. Divide both sides by h and simplify 3. Subtract both sides by \(\sf b_2\) and simplify And you're done. Tell me what you'll get :)

OpenStudy (anonymous):

I'm stuck in between A and C

OpenStudy (anonymous):

Alright. One of them is right, which is a good sign :) let's do it step by step. What will you get if you do the 1st step?

OpenStudy (anonymous):

Wait i think i actually got the answer C

OpenStudy (anonymous):

are you sure?

OpenStudy (anonymous):

Hmm thats always a trick question

OpenStudy (anonymous):

to make sure you're not guessing ;)

OpenStudy (anonymous):

Well when i put everything together that i have on my paper i get C but im thinking i did it wrong at this moment

OpenStudy (anonymous):

it would not hurt anyone if you post your solution here so that I can check it, would it? or we can work it together so that you'll see which step you switched. The decision is yours ^_^

OpenStudy (anonymous):

Well I assume you get the step 1 right. Try redoing, step 2 then step 3 :)

OpenStudy (anonymous):

Okay i see where i might've messed up at i will post my solution but right now i am most Certain its A

OpenStudy (anonymous):

why A ?

OpenStudy (anonymous):

2A = h (b1+b2) <= Times by 2 2A = h (b1+b2) /(b1+b2) = 2A/(b1=b2) = h ?

OpenStudy (anonymous):

1) Multiply both sides by 2 2\[(A)=2 \frac{ h }{ 2 } (b_{1}+b_{2})\rightarrow 2A=h (b _{1} + b _{2})\] 2) divide both sides by (b1+b2)

OpenStudy (anonymous):

SO A is Correct @Data_LG2

OpenStudy (anonymous):

Steps that you have to follow to solve for \(\sf b_1\) 1. Multiply both sides by 2 and simplify. \(\sf \color{red}{\text{2. Divide both sides by h and simplify}}\) 3. Subtract both sides by \(\sf b_2\) and simplify Step 2 is wrong. I said, divide both sides by \(\sf h\) not \(\sf (b_1+b_2)\) because if you did it, you are solving for h not b1.

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