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OpenStudy (anonymous):
Use basic trigonometric identities to simplify the expression:
3sin3 (x) csc(x) + cos2 (x) + 2cos (−x) cos (x) = ?
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OpenStudy (anonymous):
is it 3sin^3(x) or 3sin(3x)?
OpenStudy (anonymous):
oh i forgot the carets its 3sin^3 (x) csc(x) + cos ^2 (x) +2cos (-x) cos (x)
OpenStudy (anonymous):
lets start with the first term 3sin^3 (x) csc(x)
OpenStudy (anonymous):
csc(x) is the same as 1/sinx
OpenStudy (anonymous):
yess so it would be like 3sin^3 (x) 1/sinx
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OpenStudy (anonymous):
ya, so what would that simplify to?
OpenStudy (anonymous):
2sin^3?
OpenStudy (anonymous):
no, it should be 3sin^2x
OpenStudy (anonymous):
one of the sinx will cancel
OpenStudy (anonymous):
ohh okay
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OpenStudy (jdoe0001):
\(\bf 3sin^3(x) csc(x) + cos^2 (x) + 2cos (-x) cos (x)\qquad
\begin{cases}
csc(x)=\frac{1}{sin(x)}\\
cos(-x)=cos(x)
\end{cases}
\\ \quad \\
3\cancel{sin^3(x)}\cdot {\color{brown}{ \cfrac{1}{\cancel{sin(x)}} }} + cos^2 (x) + 2cos ({\color{brown}{ x}}) cos (x)
\\ \quad \\
3sin^2(x)+cos^2(x)+2cos(x)cos(x)
\\ \quad \\
\textit{what's }cos(x)cos(x)=?\)
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