Question

Find dy/dx
y=2x^3In(sinx)

Answer 1

use product formula
y=f1.f2
dy/dx=f1. d/dx(f2)+f2 d/dx(f1)

Answer 2

HI!!

Answer 3

\( y = 2x^{3ln (sinx)}\) or \(y = 2x^3 * ln (sin x)\) ???

Answer 4

\[2x^3\ln(\sin(x))\] right ?

Answer 5

yes

Answer 6

Sorry i for got to put the brackets

Answer 7

dy/dx=6x*,ln(sinx)+2x3.cot x

Answer 8

I got this:
6x^2(In(sinx))+2x^3 (cotx)

Answer 9

But the answer key is this:
2x^2(3In(sinx))+xcotx

Answer 10

So the answer key factored a 2x^2 out of each term?
Looks the same as yours besides that :p

Answer 11

oh I see, thanks!