Will give a medal to most helpful!!!!!! Solve the system of equations. x-4y=5 x=3y-2 (_,_)
First you pick the second equation cause the x is already isolated and place it in first equation in the place of x
ok.......
Then it goes like this: 3y-2-4y=5 Solving this: -7y=7 Y=-1
2 is the y intercet, right?
Now that you found y you place it in the second equation a and find x X=3.-1-2 X=6
(6,-1)
ok, so it would be (6,-1)
thank you so much :D
@DonutChip ok, how would you do it then?
I'm pretty sure that's right, but please explain how you would do it and why my resolution is wrong
nevermind lol i did my math wrong .-.
ok lol, I am going to close this question.Thank you do much @Mrs.Allison
That's ok, it is really important to expresse your opinion and point out whenever you feel something is wrong, I'm a teacher and I really liked your attitude. Good job @DonutChip
You are welcome
@Mrs.Allison your solution IS wrong 3y-2-4y=5 (is correct substitution) solving gives -y= 7 y=-7 and substituting back in second equation: x= 3(-7)-2 = -23 CHECK X BACK IN THE FIRST EQUATION: -23 - 4(-7)= 5 = correct therefore (-23,-7) is the solution
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