What transformation was performed on triangle ABC to create triangle A'B'C' ? http://static.k12.com/calms_media/media/1582000_1582500/1582241/1/48d54ad93b6e8c25f9d87135bf32cd7ca338cf92/MS_IMC-150209-150418.jpg A. rotation 90° clockwise about the origin B. rotation 180° about the origin C. translation 10 units right D. reflection across the y-axis
what happens if you slide the left triangle to right by 10 units ?
oh...... im not awake this morning :/im so sorry that was in plain day there lol
could you help me with some more please :)
you figured out the present problem
yes i did
What is the solution to the equation? \[4x^2-3=77\]
Choose all answers that are correct. A. \[5\sqrt{2}\] B. \[2\sqrt{5}\] C. \[-2\sqrt{5}\] D. \[-5\sqrt{2}\]
add 3 to both sides
that is a start
b?
4x^2 - 3 = 77 4x^2 = 80 x^2 = 20 x = +-sqrt(20) = 2sqrt(5) or -2sqrt(5)
because b = the equation with 3 added to both sides
b and c then
yep
yay!!!
What is the value of x? Round to the nearest tenth. http://static.k12.com/calms_media/media/1582000_1582500/1582244/1/db1a9a8e81a673547b04568c0c699a29005379b1/MS_IMC-150209-150421.jpg
please explain how i would do this i forgot
use pythagoras theorem leg^2 + leg^2 = hypotenuse^2
x^2 + 12^2 = 22^2 solve x
18.43?.......
rounding to nearest tenth you get 18.4
i suck at rounding even though its so easy for some people
it will be easy if u remember the positions
yeah.......
|dw:1432136069586:dw|
thank you <3 :)
np
umm i think one more for right now
Which set of side lengths defines a right triangle? A. 6, 8, 11 B. 5, 12, 13 C. 7, 9, 13 D. 6, 9, 11
i honesty dont even know this
simply use pythagoras theorem
see which lengths satisfy below equation leg^2 + leg^2 = hypotenuse^2
lets test first option A. 6, 8, 11 is below true ? 6^2 + 8^2 = 11^2
okay....
umm no
so i find which one is true?
yes, eliminate first option try second option
B. 5, 12, 13 is below true ? 5^2 + 12^2 = 13^2
that one is true
so thats the answer
awww :( i made a 60%
thats too low which ones you got wrong
umm i missed #'s 1-4 and 7,8
of course the ones i did by myself :(
oh can u attempt again
no that was the semester final D'X
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