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average rate of change??
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the answer is zero since (2-2)/(-9+1)=0 << with some dout!
h(-9) = h(-1), so average rate of change is zero.
Since average rate of change \(=\dfrac{f(b)-f(a)}{b-a}\)
oh thank you! i have another one do you mind helping?
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Sure
Ok so your average rate of change is \(\dfrac{f(3)-f(0)}{3-0}\) Can you figure what f(3) and f(0) are?
well 3-0 is 3?
Yeah, that's for denominator. it's easy part. What about numerator?
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isnt it 3 as well??
None. From graph, can you tell me what h(0) is?
im terrible at this :c so the top is 0? and the bottom is 3?
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