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Mathematics 13 Online
OpenStudy (anonymous):

average rate of change??

OpenStudy (anonymous):

http://gyazo.com/86205cdd3b8b6ebeb1aa38f7c79c9fc7 link has the question.

OpenStudy (nayef):

the answer is zero since (2-2)/(-9+1)=0 << with some dout!

geerky42 (geerky42):

h(-9) = h(-1), so average rate of change is zero.

geerky42 (geerky42):

Since average rate of change \(=\dfrac{f(b)-f(a)}{b-a}\)

OpenStudy (anonymous):

oh thank you! i have another one do you mind helping?

geerky42 (geerky42):

Sure

OpenStudy (anonymous):

http://gyazo.com/8d6bcd8eb3340ad5ee48bc7879d1fdca

geerky42 (geerky42):

Ok so your average rate of change is \(\dfrac{f(3)-f(0)}{3-0}\) Can you figure what f(3) and f(0) are?

OpenStudy (anonymous):

well 3-0 is 3?

geerky42 (geerky42):

Yeah, that's for denominator. it's easy part. What about numerator?

OpenStudy (anonymous):

isnt it 3 as well??

geerky42 (geerky42):

None. From graph, can you tell me what h(0) is?

OpenStudy (anonymous):

im terrible at this :c so the top is 0? and the bottom is 3?

geerky42 (geerky42):

|dw:1432151390505:dw|

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