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Mathematics 14 Online
OpenStudy (harley1312):

Can someone help me with my math? I will fan and medal

OpenStudy (anonymous):

I can try

OpenStudy (anonymous):

question?

OpenStudy (harley1312):

OpenStudy (harley1312):

@youngnephew34 @Mateaus

OpenStudy (youngnephew34):

I'm srry not good at it

OpenStudy (anonymous):

I can't help you. My greatest condolences.

OpenStudy (harley1312):

it's ok

OpenStudy (harley1312):

@HelpBlahBlahBlah can you help?

OpenStudy (helpblahblahblah):

I'm not good with math sorry :(

OpenStudy (harley1312):

It's fine

OpenStudy (anonymous):

I will help

OpenStudy (harley1312):

ok

OpenStudy (anonymous):

First find the square root of each value on you calculator

OpenStudy (anonymous):

then use Pythagorean theorem

OpenStudy (anonymous):

sooo you already have the hypotenuse, the square root of 267, right?

OpenStudy (anonymous):

all you need to do is subtract the square root of 11 from the square root of 267 and round to the nearest hundreth

OpenStudy (harley1312):

I'm so confused

OpenStudy (anonymous):

WOAH do we have the same problem here? Are you sure you put the right attachment?

OpenStudy (harley1312):

Sorry was looking at a different problem

OpenStudy (anonymous):

well for this one I got 13.02 rounded

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