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Mathematics 8 Online
OpenStudy (anonymous):

Please show me how to do this. (7e^x)+12=(-e^2x)

OpenStudy (isaiah.feynman):

Looks like it takes a quadratic form.

OpenStudy (isaiah.feynman):

Firstly, take -e^2x to the left side.

OpenStudy (anonymous):

@Isaiah.Feynman And then what do i do? I do not know how to pull x out of the power

OpenStudy (isaiah.feynman):

You don't have to do that, we can't even do that even if we wanted to.

OpenStudy (isaiah.feynman):

Rewrite it as \[e^{2x}+7e^{x}+12 =0\]

OpenStudy (isaiah.feynman):

Understand?

OpenStudy (anonymous):

@Isaiah.Feynman yeah

OpenStudy (isaiah.feynman):

Good. Now to find the values of x we have to do a substitution.

OpenStudy (isaiah.feynman):

Let e^x = t

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