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Please show me how to do this. (7e^x)+12=(-e^2x)
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Looks like it takes a quadratic form.
Firstly, take -e^2x to the left side.
@Isaiah.Feynman And then what do i do? I do not know how to pull x out of the power
You don't have to do that, we can't even do that even if we wanted to.
Rewrite it as \[e^{2x}+7e^{x}+12 =0\]
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Understand?
@Isaiah.Feynman yeah
Good. Now to find the values of x we have to do a substitution.
Let e^x = t
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