Question

I need someone to show me how to solve this:
Algebrically

Answer 1

I can show the way for the first system in Part A, others are the same. In first system, take the 'y' in the first equation and put it in the second equation. Like this:
\[x^2 + (3x - 5)^2 = 25\] solve for 'x'. If 'x' has a solution, it is likely it has two solutions, put both values of 'x' in the first equation, you will get two 'y' values.

Pair the 'x' values and 'y' values with each other. Those pairs are the intersection points.

Answer 2

then what

Answer 3

I have explained. Your equation will be:
\[10x^2 - 30x + 200 = 0\]
you must find 'x' values from here.

Answer 4

if thats right can you show me the next one