Debbie and Trisha are looking at the equation the square root of the quantity of 4 times x minus 6 equals square root of x . Debbie says that the solution is extraneous. Trisha says that the solution is non-extraneous. Is Debbie correct? Is Trisha correct? Are they both correct? Justify your response by solving this equation, explaining each step with complete sentences.
Someone please help! I will reward medal and fan!!
@grex10
Do you get this? @leon549
yeah working on it
extraneous A solution to an equation that SEEMS to be right, but when we check it (by substituting it into the original equation) turns out NOT to be right.
So then who is correct?
@lilcj2001
i will go with debbie
Why?
the equation will become 4x -6= sqrt x
square both sides to get a general equation
hey there, let's work it out and find what is happening
\[\sqrt{4x-6}=\sqrt{x}\] this is our equation yes
as leon said we take square of both sides to solve this
\[(\sqrt{4x-6})^2=(\sqrt{x})^2 \Longrightarrow 4x-6=x \] \[4x-x=-6\] can you solve this one?
should be 4x-x=6 not -6 sorry
\[4x-x=6 \]
so can you solve it or need help with that one?
well @LexiLuvv2431 what do say?
Heyy thank you. Umm I kinda think I get it but at the same time I dont know where to start.
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