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Find the area of the rectangle. Fan and Medal 15x + 1 <-- 56x^2 +8x 56x + 8 15x^2 + 9x NOTE* Rectangle is attached below *NOTE
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|dw:1432336230404:dw|
@jagr2713
@geerky42
No. To find area of rectangle, you just multiply length by width, right? So you have \(8x(7x+1)=~?\)
57
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@geerky42
@geerky42 @geerky42 @geerky42 @geerky42
@iGreen @TheSmartOne @jagr2713
57? What does that mean
I have no idea s/he confused me
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\[8x(7x+1) \implies 8x \times 7x+8x \times 1\]
x is a variable you leave it alone, and when you're multiplying with variables use the following property. \[x \times x = x^2\]
Was I right, is it A?
No, I'm not sure how you got that, but you must distribute the 8x over 7x+1 |dw:1432337260303:dw|
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