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\[32^\frac{ 4 }{ 5 }\]
This problem confuses me once it turns into a radical
\[\sqrt[5]{32^4}\]
what does 32 equal in terms of 2 to a power?
in other words, find x in this: \[\huge 2^x=32\]
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4
no its 5
but anyway. Now you have to simplify this:\[\huge (2^5)^\frac{4}{5}\]
Okay so I got 2^4 which then equal 16? @Rizags
yes
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okay one more
\[64^\frac{ 2 }{ 3 }\]
\[\sqrt[3]{64^2}\]
what is the first step
rewrite 64 in power of 2
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\[2^6=64\]
Okay I get it now 16 is the answer
Thanks for helping me @Rizags
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