Please help! Caley has a bag that contains 9 blue marbles and 13 yellow marbles. She selects a marble at random, and then, without replacing the first one, selects another marble at random. What is the probability that Caley selects a blue marble and then a yellow marble? Round your answer to the nearest percent. P(blue and yellow) ≈ ______%
what is the probability of picking a blue marble?
Idk lol
how many blue marbles are there? how many marbles are there total?
What is the probability that Caley selects a blue marble and then a yellow marble?
we'll get there, first answer these two subquestions how many blue marbles are there? how many marbles are there total?
Oh sorry 9 and 22
so the probability of picking blue is the fraction 9/22
after one marble is taken out, there are 22-1 = 21 marbles left there are 13 yellow marbles which is why the probability of picking yellow, after you pick blue, is 13/21
multiply these two fractions out (9/22)*(13/21) = ??
39/54
i ment 139/54
@jim_thompson5910
(9/22)*(13/21) = 39/154 which is approximately 0.2532 convert 0.2532 to a percentage to get 25.32% then round this to the nearest percent to get 25%
okay thank you!
np
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