can someone help me with 4 questions
A bag contains 4 white, 3 blue, and 5 red marbles Find the probability of choosing a red marble, then a white marble if the marbles are replaced.
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OpenStudy (anonymous):
How many red marbles are there?
OpenStudy (anonymous):
5
OpenStudy (anonymous):
How many total marbles?
OpenStudy (anonymous):
12
OpenStudy (anonymous):
So red-marbles/total-marbles would be what?
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OpenStudy (anonymous):
5/12
OpenStudy (anonymous):
Now do the same thing with white marbles and total marbles.
OpenStudy (anonymous):
4/12
OpenStudy (anonymous):
which would simplify to?
OpenStudy (anonymous):
5/6
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OpenStudy (anonymous):
How does 4/12 simplify to 5/6?
OpenStudy (anonymous):
sorry I mean 1/12
OpenStudy (anonymous):
How does 4/12 simplify to 1/12?
OpenStudy (anonymous):
A 1/12
B 5/36
C 5/6
D 5/12
A 1/12
B 5/36
C 5/6
D 5/12
A 1/12
B 5/36
C 5/6
D 5/12
OpenStudy (anonymous):
Uh, what?
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OpenStudy (anonymous):
these are the chocies to chose from
OpenStudy (anonymous):
Ok, but let's get back to what we're working on. What does 4/12 simplify to?
OpenStudy (anonymous):
I don't know
OpenStudy (anonymous):
What does 4/4 equal? What does 12/4 equal?
OpenStudy (anonymous):
4/4 = 1
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OpenStudy (anonymous):
And 12/4?
OpenStudy (anonymous):
3
OpenStudy (anonymous):
So \[\frac{ 4/4 }{ 12/4 }\] would be what?
OpenStudy (anonymous):
but 1/3 is not a chioic to chose from
OpenStudy (anonymous):
A 1/12
B 5/36
C 5/6
D 5/12
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OpenStudy (anonymous):
Ok, now we have the fractions. 5/12 and 1/3. Now multiply the fractions.
OpenStudy (anonymous):
my calculator doesn't do fractions
OpenStudy (anonymous):
You don't need a calculator for this. It's just\[\frac{ 5 }{ 12 }*\frac{ 1 }{ 3 }\]
OpenStudy (anonymous):
5/36
OpenStudy (anonymous):
And that is your answer.
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OpenStudy (anonymous):
so the answer is b 5/36 right
OpenStudy (anonymous):
Yes, I just said so.
OpenStudy (anonymous):
can you help me with the other 3 plz
OpenStudy (anonymous):
I will if you tag me in a separate question.
OpenStudy (anonymous):
using the same info A bag contains 4 white, 3 blue, and 5 red marbles Find the probability of choosing 3 blue marbles in a row if the marbles are replaced
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OpenStudy (anonymous):
@LegendarySadist
OpenStudy (anonymous):
hello u still there
OpenStudy (anonymous):
@LegendarySadist
OpenStudy (anonymous):
@Loser66
OpenStudy (anonymous):
@Loser66 and legendarsadist will u help me with the three questions plz plz
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OpenStudy (anonymous):
using the same info A bag contains 4 white, 3 blue, and 5 red marbles Find the probability of choosing 3 blue marbles in a row if the marbles are replaced
OpenStudy (loser66):
The probability of blue marbles is 1/4 for each time, right? (That is from \(\dfrac{blue}{total}\)
OpenStudy (anonymous):
A 2/11
B 1/220
C 1/27
D 1/64
OpenStudy (loser66):
After pick it out, then replace, second time around, the situation repeats. This time, the result is exactly what it happen in the first time: 1/4
OpenStudy (loser66):
Third time, same
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OpenStudy (loser66):
Hence, the final result is (1/4)*(1/4)*(1/4) = ????