The age of father was twice the square of the age of his son.Eight years,hence,The age of the father will be 4 years more than 3 times the age of his son.Find their present ages.

Question

kropot72 · Answer

Should this question read as follows:
"The age of father is twice the square of the age of his son. Eight years hence, the age of father will be 4 years more than 3 times the age of his son. Find their present ages."

aaronandyson · Answer

@Sepeario

sepeario · Answer

Yes @kropot72 the question doesn't actually make sense otherwise.

sepeario · Answer

If the age of the father is x and the age of the son is y, then we get the simultaneous equations: $$x=2y^2$$ and also $$x+8=4+3(y+8)$$

sepeario · Answer

I think..

sepeario · Answer

If you rearrange the second equation you get $$x=3y+20$$ and then you substitute the first equation into the second, leaving $$2y^2=3y+20$$ or $$2y^2-3y-20=0$$

sepeario · Answer

You can then factorise this polynomial equation.

sepeario · Answer

Giving (2y+5)(y-4), leaving the solutions for y at either 4 or -5/2

aaronandyson · Answer

4 and 32

sepeario · Answer

There you go!

sepeario · Answer

Yes exactly.