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Mathematics 13 Online
OpenStudy (anonymous):

Find the number of permutations of the first 12 letters taken 3 at a time ?

OpenStudy (anonymous):

@dan815 @triciaal

OpenStudy (anonymous):

@Hero

OpenStudy (triciaal):

12P3 = 12!/(3!9!)

OpenStudy (anonymous):

1320

OpenStudy (anonymous):

@triciaal In how many ways can a teacher arrange 10 students in the front row if there are 60 total students?

OpenStudy (triciaal):

* correction we do not divide when it is not specific

OpenStudy (anonymous):

@triciaal so 1320 isnt the correct answer?

OpenStudy (triciaal):

permutations and combinations the possible arrangements and specific arrangement

OpenStudy (anonymous):

i dont understand what you mean @triciaal

OpenStudy (triciaal):

how many ways can you choose 3 starting with 12 12 * 11* 10 = 1320

OpenStudy (anonymous):

alright so i got it correct @triciaal

OpenStudy (anonymous):

@triciaal In how many ways can a teacher arrange 10 students in the front row if there are 60 total students?

OpenStudy (triciaal):

now I think we divide there are 6 groups of 10 for 60 but the combinations are important once a particular student is chosen then no longer in the "pool" to be chosen for the front row

OpenStudy (anonymous):

nPr= 60!/(60-10)!

OpenStudy (triciaal):

|dw:1432517774548:dw| not sure do you have the choices ?

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