Find the number of permutations of the first 12 letters taken 3 at a time ?
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OpenStudy (anonymous):
@dan815 @triciaal
OpenStudy (anonymous):
@Hero
OpenStudy (triciaal):
12P3 = 12!/(3!9!)
OpenStudy (anonymous):
1320
OpenStudy (anonymous):
@triciaal In how many ways can a teacher arrange 10 students in the front row if there are 60 total students?
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OpenStudy (triciaal):
* correction we do not divide when it is not specific
OpenStudy (anonymous):
@triciaal so 1320 isnt the correct answer?
OpenStudy (triciaal):
permutations and combinations the possible arrangements and specific arrangement
OpenStudy (anonymous):
i dont understand what you mean @triciaal
OpenStudy (triciaal):
how many ways can you choose 3 starting with 12
12 * 11* 10 = 1320
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OpenStudy (anonymous):
alright so i got it correct @triciaal
OpenStudy (anonymous):
@triciaal In how many ways can a teacher arrange 10 students in the front row if there are 60 total students?
OpenStudy (triciaal):
now I think we divide
there are 6 groups of 10 for 60 but the combinations are important
once a particular student is chosen then no longer in the "pool" to be chosen for the front row
OpenStudy (anonymous):
nPr= 60!/(60-10)!
OpenStudy (triciaal):
|dw:1432517774548:dw|
not sure
do you have the choices ?