Question

(9-^6)^3=9

Answer 1

\[\huge\rm (9^{-6})^3=9\]
like this ?

Answer 2

Yes do you know the answer? I can't get it

Answer 3

yes so
u have to apply 2 exponent rule
first one is \[\huge\rm (x^m)^n = x^{ m \times n}\]
multiply outside exponent of number by inside exponent

Answer 4

2nd exponent rule:
\[\huge\rm x^{-m} = x^\frac{ 1 }{ m }\]
if there is a negative exponent, change that to 'ts reciprocal

Answer 5

So the answer is X1/m?

Answer 6

\[\huge\rm (9^{-6})^3=9\]
it's ur question
so multiply outside exponent by inside exponent of 9

Answer 7

So what is the answer? 9? Please

Answer 8

i told you how you have to solve
\[\huge\rm 9^{-6 \times 3} = 9\]
-6 times 3 = what
btw what's the statement
what topic is it ?

Answer 9

Thank you!

Answer 10

we' aren't done yet
is it log unit ?