Question

What is the equation of a line that passes through (-6, 2) and has a slope of −12 ?

Answer 1

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Answer 2

\[y-y1=m(x-x1) \]
slope = -12
x1=-6
y1=2

Answer 3

Just plug everything in and solve :)

Answer 4

y=x2−2

y=−x2−1

y=2x+1

y=−2x−1

Answer 5

Do what i told u to do above

Answer 6

in y = mx + b form the slope is in the m position
so m = -12
your points (-6,2)....x = -6 and y = 2
now we already know the slope (m) and our points (x,y)....so basically we just need to find b, the y intercept.
So we sub into the formula and find b
y = mx + b
2 = -12(-6) + b
2 = 72 + b
2 - 72 = b
-70 = b

so your equation becomes : y = -12x - 70
questions ?

Answer 7

thanks