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verify the identity, tan(x+pi/2)=-cot x
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\[\huge\rm tan(x + y ) = \frac{ \tan x + \tan y }{ 1- \tan x \times \tan y }\] use this formula
pi/2 = 90 degree what is cos and sin value at 90 degree ?
I'm not really sure.
nah forget that's wrong
*wait 4 someone else*
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Sure, thanks.
\[\tan(x+\pi/2)=\frac{ \sin (x+\pi/2) }{ \cos(x+\pi/2) }=\frac{ sinx \cos \pi/2+\cos x \sin \pi/2 }{ \cos x \cos \pi/2-sinx \sin \pi/2 }\]
\[\sin \pi/2=1 , \cos \pi/2 =0\]
That verifies the identity?
yep
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Thanks.
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