An arrow is shot vertically upward from a platform 39 ft high at a rate of 167 ft per sec. When will the arrow hit the ground? Use the formula: h = −16t2 + v0t + h0. (Round your answer to the nearest tenth.)

Question

An arrow is shot vertically upward from a platform 39 ft high at a rate of 167 ft per sec.  When will the arrow hit the ground?  Use the formula:  h = −16t2 + v0t + h0.  (Round your answer to the nearest tenth.)

anonymous · Answer

I got an answer of 10.7 seconds

radar · Answer

Assuming that the arrow was shot vertically, it will return vertically and hit the platform, never hitting the ground.

radar · Answer

When it does hit the platform it will be traveling at -167 ft/sec, the same speed it left but in the opposite direction.

radar · Answer

I don't believe that is what the question is really asking.

anonymous · Answer

It wants me to use the quadratic formula

anonymous · Answer

the answer i get is $$10.66 \approx 10.7 feet/second$$
we have to assume it will reach the ground, as if we shoot it standing in a platform, but over its border...