Question

What is the equation of the line that is perpendicular to -x + y = 7 and passes through (-1, -1)?

-x + y = 2
-x – y = 2
x – y = 2
-x – y = 0
x + y = 0

Answer 1

1. find the slope of the original equation
2. take the negative reciprocal of the slope obtained in step 1
3. write an equation in the form y = mx + b, using the slope obtained in step 2 and the coordinates (-1,-1)
4. rewrite the equation in standard form

Answer 2

can u walk me through each step

Answer 3

Here you go

Answer 4

@Vocaloid

Answer 5

what steps are you confused about?

Answer 6

1. find the slope of the original equation

-x + y = 7
y = x + 7, so the original slope is 1

2. take the negative reciprocal of the slope obtained in step 1

the negative reciprocal of the original slope is -1

3. write an equation in the form y = mx + b, using the slope obtained in step 2 and the coordinates (-1,-1)

y = mx + b
-1 = (-1)(-1) + b
b = -2

so y = -x -2

4. rewrite the equation in standard form

y = -x -2
-x - y = 2

Answer 7

A plot of the lines is attached