Question

Can you help me?
Simplify
x^2+13x+40/x-7 ÷ x+8/x^2-2a

Answer 1

are you sure theres an (a) at the end?

Answer 2

oh no yeah your right, let me fix it

Answer 3

I'd start by factoring the quadratics....

then when you divide by a fraction, you take the reciprocal and multiply

Answer 4

x^2+13x+40/x-7 ÷ x+8/x^2-49

Answer 5

so can you factor the quadratics...?

Answer 6

-6x3 + 13x2 + 8x - 9 / x correct?

Answer 7

no its

\[\frac{(x +8)(x +5)}{(x -7)} \div \frac{(x + 8)}{(x + 7)(x - 7)}\]

now apply the rule for dividing by fractions, flip and multiply

\[\frac{(x + 8)(x + 5)}{(x -7)} \times \frac{(x - 7)(x + 7)}{(x + 8)}\]

remove the common factors and multiply

Answer 8

13x/6x × 15x something like that? or am i way off????

Answer 9

ok.... let me write it this way.

remember, multiplying 2 fractions, multiply the numerators and multiply the denominators

\[\frac{(x + 5)(x + 8)(x - 7)(x + 7)}{(x + 8)(x - 7)}\]

what common factors do you see..?

Answer 10

i see (x+8) and (x-7) as common factors. right?