The population of a local species of flies can be found using an infinite geometric series where a1 = 940 and the common ratio is one fifth. Write the sum in sigma notation, and calculate the sum (if possible) that will be the upper limit of this population.
@campbell_st
you have a question where there is a limitings sum because the common ratio is lies between -1 and 1 so the terms in the sum are \[a_{1} = 940, ~~a_{2} = 940 \times \frac{1}{5}, ~~a_{3} = 940 \times (\frac{1}{5})^2... \] so the sum notation is \[\sum_{n=1}^{\infty} 940\times (\frac{1}{5})^{n -1}\] the limiting sum is \[S_{\infty} = \frac{a}{1 - r}\] from the question r = 1/5 and a = 940
so I need to now plug in those values into the limiting sum equation?
so the sum would be 1175
so the answer would be A
I haven't done the calculation.... hold on so 1175 seems correct
Okay great!!
and it is true that n-1 is the same thing as i-1?
same thing
awesome! Thank you for your help!
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