notice that the height of the triangles is 12
the whole shape's height is 17
that means if you extend the height of the triangle to the end of the shape you get \(12+x=17\)
OpenStudy (alurahenderson):
5
OpenStudy (alurahenderson):
I don't know why I put 2
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OpenStudy (alyssa_xo):
|dw:1432754292136:dw|
area of a trapezoid = \(\dfrac{a+b}{2}h=\dfrac{14+18}{2}*5=\dfrac{32}{2}*5=16*5=80\)
next, we find the area of the triangles
OpenStudy (alurahenderson):
Okay, is 9 the width because it's half of the bottom of the top shape?
OpenStudy (alyssa_xo):
that isn't necessary as we'd be adding up the 2 triangles anyways. recall that \(Area(\Delta)=\dfrac{bh}{2}\)
OpenStudy (alurahenderson):
oh
OpenStudy (alyssa_xo):
if you don't believe me you can break it up or do it as a whole.|dw:1432754774085:dw|
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OpenStudy (alurahenderson):
oh! okay see I didn't understand what you were saying at first I get it now it would be 108?
OpenStudy (alyssa_xo):
mhm
108+the other area is the whole thing
OpenStudy (alurahenderson):
216
OpenStudy (alyssa_xo):
hm? I thought the other area was 80
OpenStudy (alurahenderson):
oh im sorry I thought you meant not to half to triangles and add those
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OpenStudy (alurahenderson):
188
OpenStudy (alyssa_xo):
oh, you added up the triangle twice
the reason I drew it out was because I wanted to demonstrate that you could either take the area of the whole triangle (0.5*12*18=108)
or you could do the 2 triangles (0.5*12*9)+(0.5*12*9)=108
OpenStudy (alyssa_xo):
yeah
OpenStudy (alurahenderson):
Okay, Thank you very much :}
OpenStudy (alyssa_xo):
you're welcome ;)
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