Question

What is 9th term of the arithmetic sequence whose 2nd and 6th terms are 107 and 87, respectively?

Answer 1

@jakashaka123

Answer 2

17?

Answer 3

To find the common difference d, use the formula
a1+4d=a5.
For us, a1 is
10 and a5 is 38.
10+4d=38
Now we can solve for d.
4d=28
d=7
Add the common difference to the first term to get the second term.
a2=a1+d=10+7=17

Answer 4

yes its 17

Answer 5

Otay :)

Answer 6

np

Answer 7

No its not 17 :P

Answer 8

Mike .-. Stop bursting my bubble D':<

Answer 9

I know trust me, ive literally been up 12 hours trying to do this lol. ive been wrong almost all night xD

Answer 10

^^^ are the possible answers.

Answer 11

Go slap that h o e they be wrong den!

Answer 12

Lmfao

Answer 13

▄︻̷̿┻̿═━一 The H O E ===> ʕ•ᴥ•ʔ

Answer 14

(ง'̀-'́)ง

Answer 15

Yeah I wish... I dont even know who the hoe is xD

Answer 16

His name is sam! ┬┴┬┴┤(･_├┬┴┬┴ S H I T he's coming hide! I gtg ttyl

Answer 17

Lol xD

Answer 18

@jakashaka123 Can you help?

Answer 19

@iGreen @ZeHanz

Answer 20

@Vianne can you help?

Answer 21

Any help would be great!

Answer 22

There is no need for formulas in this case, because the numbers are small as are the differences between the terms involved.

There are four steps to go from the second to the 6th term. each step is the same size (arithmetic seq).
In those four steps you go from 107 to 87, so 20 less. That is 20/4=5 less each step.
I think you know now how to find the ninth number :)

Answer 23

so 122 then?

Answer 24

No, because the sequence decreases: 2th term is 107, 6th is 87.
Each next term is 5 less than the current one.

Answer 25

ops sorry, wrong way, so 72 lmao

Answer 26

Done!

Answer 27

Thank you sooo much :D