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Mathematics 7 Online
OpenStudy (is3535):

A jewelry stand sells 5 different pairs of earrings. The earrings sell for $12, $9, $6, $8, and $10. What is the mean absolute deviation of the prices? Round to the nearest cent, if necessary.

OpenStudy (is3535):

@SickTwistd

OpenStudy (anonymous):

i know MAD

OpenStudy (anonymous):

Give me a sec plz

OpenStudy (is3535):

12+9+6+8+10=45 divided by 5=9 the mean absolute deviation is 9

OpenStudy (anonymous):

No its 2.4

OpenStudy (is3535):

so 2.4

OpenStudy (anonymous):

All the #'s added up, then / that # by how many #'s there are, then subtract that from all of the #'s, then take the distance from all of those numbers to zero and divide it by... one sec sorry

OpenStudy (anonymous):

its a bit complicated

OpenStudy (is3535):

@Vocaloid

OpenStudy (is3535):

so 2.4

OpenStudy (is3535):

or 9

OpenStudy (anonymous):

2.4

OpenStudy (is3535):

ok

OpenStudy (is3535):

A quality-control center finds that 2 out of 250 toy trains are defective. How many trains would they expect to be defective in a batch of 10,000? A. 250 B. 125 C. 80 D. 40

OpenStudy (anonymous):

r u in k12?

OpenStudy (anonymous):

sorry im late

OpenStudy (anonymous):

@is3535 ?

OpenStudy (anonymous):

i just joined yesterday, so this is all new to me XD

OpenStudy (anonymous):

:D

OpenStudy (is3535):

yes

OpenStudy (anonymous):

im i k12 yea

OpenStudy (anonymous):

me 2. what grade?

OpenStudy (anonymous):

7th

OpenStudy (is3535):

|dw:1432841369245:dw|

OpenStudy (is3535):

80

OpenStudy (is3535):

A quality-control center finds that 2 out of 250 toy trains are defective. How many trains would they expect to be defective in a batch of 10,000? A. 250 B. 125 C. 80 D. 40

OpenStudy (anonymous):

im in 7th. lol im REALLy good @ math. if i were in a room of 100 people, i would be better than 96 of them. based on my scantron

OpenStudy (anonymous):

80

OpenStudy (anonymous):

anyways, ive gtg do MY K12 work. ttyl! have a gr8 day!

OpenStudy (anonymous):

and i agree 80.

OpenStudy (anonymous):

thanks anyone have twitter?

OpenStudy (anonymous):

this cal. will help btw :) http://www.alcula.com/calculators/statistics/mean-absolute-deviation/

OpenStudy (anonymous):

i do. its TheOrion101

OpenStudy (anonymous):

if u do, follow me @johnnycahun

OpenStudy (anonymous):

kk i will if i can. Bye!

OpenStudy (anonymous):

I'll follow u orion

OpenStudy (anonymous):

;) bye

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