Question

Can someone walk me through these and help me get the right answer .... A quadrilateral has vertices (2, 0), (0, –2), (–2, 4), and (–4, 2). Which special quadrilateral is
formed by connecting the midpoints of the sides?

kite
rectangle
trapezoid
rhombus

2. Which of the following describes TVS? The vertices are T(1, 1), V(4, 0), and S(3, 5)
isosceles
scalene
right
equilateral

4. Verify that parallelogram ABCD with vertices A(–5, –1), B(–9, 6), C(–1, 5), and D(3, –2) is a
rhombus by showing that it is a parallelogram with perpendicular diagonal

Answer 1

hi

Answer 2

Heyy :)

Answer 3

Plot each point, then, Connect the middle of each side and see what you get

Answer 4

I got a rectangle too! okay thanks

Answer 5

The dotted part is the connected midpoints, that is what the first shape answer is

Answer 6

How would I solve the second one ? @DanJS

Answer 7

The first one is not a rectangle, the dotted shape does not have right angles

Answer 8

hmmm so would it be a trapaoid? or a rhombus?

Answer 9

It is a parallelogram, but that isnt an answer, so i believe this is what it is...
http://en.wikipedia.org/wiki/Kite_%28geometry%29

Answer 10

a rhombus has all 4 sides of equal length, this one here does not

Answer 11

a trapazoid has only one pair of parallel sides, this one has 2 pairs

Answer 12

It is not a rectangle, so it must be the Kite

Answer 13

OHH yhea it would be Kite I see it now

Answer 14

The second prob....

You have to figure the lengths of each side of the triangle...
Equilaterla = all 3 sides the same
isosceles = 2 sides the same
scalene = all sides different
right = 90 degree angle

Answer 15

Did you learn the distance formula between 2 points?

Answer 16

Yhea , its a squared + b squared = c squared right ?

Answer 17

\[distance = \sqrt{(5-1)^2+(3-1)^2}\]