Mathematics
9 Online
OpenStudy (anonymous):
given the triangle below, find sec X, tan X, and cos Z in fraction form (pic included)
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OpenStudy (anonymous):
|dw:1432958949158:dw|
OpenStudy (anonymous):
Hello :)
OpenStudy (anonymous):
are you there?
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
lol do you know how to do this one?
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OpenStudy (anonymous):
yep
OpenStudy (anonymous):
are you familiar with SOH CAH TOA?
OpenStudy (anonymous):
sort of
OpenStudy (anonymous):
ok, lets find cos Z first
OpenStudy (anonymous):
how?
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OpenStudy (anonymous):
cos z= adj/hyp
OpenStudy (anonymous):
|dw:1432959576632:dw|
OpenStudy (anonymous):
so 15 / 25? or?
OpenStudy (anonymous):
thats right
OpenStudy (anonymous):
.6
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OpenStudy (anonymous):
they said in fraction form so 15/25 or 3/5 work
OpenStudy (anonymous):
oh.. okay so cos z = 3/5 .. whats next? :/
OpenStudy (anonymous):
find tanx
OpenStudy (anonymous):
how?
OpenStudy (anonymous):
Find the missing side
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OpenStudy (anonymous):
use pythagorean
OpenStudy (anonymous):
Do you know how to do that
OpenStudy (anonymous):
so a^2 + b ^ = c^?
OpenStudy (anonymous):
thats right
OpenStudy (anonymous):
25 = c
625 - 225 = 400
20
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OpenStudy (anonymous):
good job
now find tanx
OpenStudy (anonymous):
25 / 20 or 20/ 25?
OpenStudy (anonymous):
opposite / adjacent
OpenStudy (anonymous):
15 / 20
3/ 4
OpenStudy (anonymous):
well done
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OpenStudy (anonymous):
what about secx
OpenStudy (anonymous):
now sec x
OpenStudy (anonymous):
whats the formula?
OpenStudy (anonymous):
secx = 1/cosx
OpenStudy (anonymous):
20 / 15?
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OpenStudy (anonymous):
how do i do that?
OpenStudy (anonymous):
is cos opposite/adjacent
adjacent/hypotenuse
or opposite/hypotenuse
OpenStudy (anonymous):
opposite / hypotenuse
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
Try to remember SOH CAH TOA
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OpenStudy (anonymous):
SOH: sin = opposite/hypotenuse
OpenStudy (anonymous):
CAH: cos = adjacent/hypotenuse
OpenStudy (anonymous):
TOA: tan = opposite/adjacent
OpenStudy (anonymous):
so 15 / 25?
OpenStudy (anonymous):
nope
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OpenStudy (anonymous):
remember sec = 1/cos
OpenStudy (anonymous):
the hypotenuse is 25?
OpenStudy (anonymous):
cos is adjacent/hypotenuse
OpenStudy (anonymous):
take the reciprocal to get hypotenuse/adjacent
OpenStudy (anonymous):
secx=hypotenuse/adjacent
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OpenStudy (anonymous):
|dw:1432960516695:dw|
OpenStudy (anonymous):
Don't forget, we're looking at x
OpenStudy (anonymous):
so 20 /25 or 25 / 20?
OpenStudy (anonymous):
hyotenuse/adjacent
OpenStudy (anonymous):
25 / 20
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OpenStudy (anonymous):
5/4, good job
OpenStudy (anonymous):
awesome! thanks :)