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Mathematics 9 Online
OpenStudy (anonymous):

given the triangle below, find sec X, tan X, and cos Z in fraction form (pic included)

OpenStudy (anonymous):

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OpenStudy (anonymous):

Hello :)

OpenStudy (anonymous):

are you there?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

lol do you know how to do this one?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

are you familiar with SOH CAH TOA?

OpenStudy (anonymous):

sort of

OpenStudy (anonymous):

ok, lets find cos Z first

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

cos z= adj/hyp

OpenStudy (anonymous):

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OpenStudy (anonymous):

so 15 / 25? or?

OpenStudy (anonymous):

thats right

OpenStudy (anonymous):

.6

OpenStudy (anonymous):

they said in fraction form so 15/25 or 3/5 work

OpenStudy (anonymous):

oh.. okay so cos z = 3/5 .. whats next? :/

OpenStudy (anonymous):

find tanx

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

Find the missing side

OpenStudy (anonymous):

use pythagorean

OpenStudy (anonymous):

Do you know how to do that

OpenStudy (anonymous):

so a^2 + b ^ = c^?

OpenStudy (anonymous):

thats right

OpenStudy (anonymous):

25 = c 625 - 225 = 400 20

OpenStudy (anonymous):

good job now find tanx

OpenStudy (anonymous):

25 / 20 or 20/ 25?

OpenStudy (anonymous):

opposite / adjacent

OpenStudy (anonymous):

15 / 20 3/ 4

OpenStudy (anonymous):

well done

OpenStudy (anonymous):

what about secx

OpenStudy (anonymous):

now sec x

OpenStudy (anonymous):

whats the formula?

OpenStudy (anonymous):

secx = 1/cosx

OpenStudy (anonymous):

20 / 15?

OpenStudy (anonymous):

how do i do that?

OpenStudy (anonymous):

is cos opposite/adjacent adjacent/hypotenuse or opposite/hypotenuse

OpenStudy (anonymous):

opposite / hypotenuse

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

Try to remember SOH CAH TOA

OpenStudy (anonymous):

SOH: sin = opposite/hypotenuse

OpenStudy (anonymous):

CAH: cos = adjacent/hypotenuse

OpenStudy (anonymous):

TOA: tan = opposite/adjacent

OpenStudy (anonymous):

so 15 / 25?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

remember sec = 1/cos

OpenStudy (anonymous):

the hypotenuse is 25?

OpenStudy (anonymous):

cos is adjacent/hypotenuse

OpenStudy (anonymous):

take the reciprocal to get hypotenuse/adjacent

OpenStudy (anonymous):

secx=hypotenuse/adjacent

OpenStudy (anonymous):

|dw:1432960516695:dw|

OpenStudy (anonymous):

Don't forget, we're looking at x

OpenStudy (anonymous):

so 20 /25 or 25 / 20?

OpenStudy (anonymous):

hyotenuse/adjacent

OpenStudy (anonymous):

25 / 20

OpenStudy (anonymous):

5/4, good job

OpenStudy (anonymous):

awesome! thanks :)

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