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Mathematics 19 Online
OpenStudy (kobeni-chan):

FAN and MEDAL! :) Prove: sin θ - sin θ•cos^2 θ = sin3 θ. You must show all work. I think I use the Pythagorean Identity with this one?

OpenStudy (anonymous):

I think you're right :)

OpenStudy (anonymous):

But in case you need reassurance, try eliminating a common factor and see if the remaining terms look familiar

OpenStudy (anonymous):

shouldn't it be sin^3 θ not Sin 3θ ??

OpenStudy (kobeni-chan):

Oh sorry about that. I forgot to fix it so it read as an exponent >_< sin^3 θ

OpenStudy (kobeni-chan):

Should I divide by sin θ to make it all 1 - cos^2 θ = sin^2 θ? Ohh so it'll be sin^2 θ + cos^2 θ = 1 when i move the cos around.

OpenStudy (kobeni-chan):

Thanks guys :) Sorry I cant give out more than 1 medal.

OpenStudy (anonymous):

haha it's alright

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