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Mathematics 24 Online
OpenStudy (anonymous):

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OpenStudy (haleyelizabeth2017):

Well, to begin with, do you know the distance formula?

OpenStudy (haleyelizabeth2017):

Okay. So set the distance formula up to where it equals \(\sqrt{73}\) Okay?

OpenStudy (haleyelizabeth2017):

Then plug in our points (n will be x1) and once you get there, show me :)

OpenStudy (haleyelizabeth2017):

its the distance formula....there is x1, y1, x2 and y2 that you need to plug in...I'll just show you lol

OpenStudy (haleyelizabeth2017):

yes

OpenStudy (haleyelizabeth2017):

Oops....then, square both sides to cancel the sqrts \[(\sqrt73)^2=(\sqrt{((-3)-(n))^2+((11)-(8))^2}~~)^2\] \[73=(-3-n)^2+(11-8)^2\] \[73=(-3-n)^2+(3)^2\] \[73=(-3-n)^2+9\] You got an idea of what to do next?

OpenStudy (haleyelizabeth2017):

Okay, that's perfectly fine :P

OpenStudy (haleyelizabeth2017):

\[73=(-3-n)^2+9\] so we have this ^^ and we need to be able to get n isolated. So we need to subtract 9 from both sides and then square root both sides. \[\sqrt{64}=\sqrt{(-3-n)^2}\] \[8=-3-n\] \[n+8=-3\] \[n=-11\]

OpenStudy (haleyelizabeth2017):

you're welcome!

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