Use the quadratic formula to solve 2y2 – 3y = 2.

A.
{½, 2}

B.
{½, –2}

C.
{–½, –2}

D.
{–½, 2}

Question

Use the quadratic formula to solve 2y2 – 3y  = 2.
 
 A.
{½, 2}
 
 B.
{½, –2}
 
 C.
{–½, –2}
 
 D.
{–½, 2}

pooja195 · Answer

Before the subtract the 2 so the the equation is = to 0 
$$\huge 2y^2-3y-2$$

pooja195 · Answer

What are your 
a
b
c
values?

pooja195 · Answer

Once you have those we can plug it into this equation AKA Quadratic Formula

pooja195 · Answer

$$\huge~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$$

anonymous · Answer

I barley started to learn this, do you think you can walk me through it, step by step?

pooja195 · Answer

$$\huge~ax^2+bx+c$$
$$\huge~2y^2-3y-2=0$$
Anything that is ^2 will be the A just tell the number ignore the y^2
then anything with a plain vairble will just be the b value in this case it is -3
A number alone is the C value which in this case is -2

pooja195 · Answer

Got it so far?

anonymous · Answer

yes

anonymous · Answer

@pooja195

pooja195 · Answer

Good now we plug it in

kendricklamar2014 · Answer

Step 1. Subtract 2 from both sides:
$$2y^2−3y−2=2−2$$
$$= 2y^2−3y−2=0$$

anonymous · Answer

okay! @KendrickLamar2014

kendricklamar2014 · Answer

Step 2. Factor the Left side:
$$(2y+1)(y−2)=0$$

pooja195 · Answer

$$\huge~x=\frac{ -(-3)\pm \sqrt{(-3)^2-4(2)(-2)} }{ 2(2) } $$

kendricklamar2014 · Answer

Step 3. Set the factors to equal 0:
$$2y+1=0~ or ~y−2=0$$

pooja195 · Answer

@KendrickLamar2014 it says to use the quadratic formula not factoring

kendricklamar2014 · Answer

I know, but you can get the same answer.

pooja195 · Answer

They need to use the quadratic formula its the directions.

kendricklamar2014 · Answer

$$= y = -\frac{ 1 }{ 2 }~or~ y = 2$$

pooja195 · Answer

Or just give them the answer...... @ninowletonzalez06 are you allowed to use factoring?

kendricklamar2014 · Answer

Yah, I was just showing her that there are many ways to solve this equation

pooja195 · Answer

Or have u not learned it because the Quadratic formula comes before factoring @KendrickLamar2014

pooja195 · Answer

Well now i bet that the asker is confused .-.

anonymous · Answer

a liitle, can you explain it in the easiest form!

pooja195 · Answer

do you HAVE to use the quadratic formula?

anonymous · Answer

by what the question is asking yes!

anonymous · Answer

are you still there?

pooja195 · Answer

Ok :) 
All i did here was plug in the values

pooja195 · Answer

LaTex isnt working i cant finish it .-.

pooja195 · Answer

$$\huge~x=\frac{ -(-3) \pm \sqrt{(-3)^2-4(2)(-2)} }{ 2(2)} $$

anonymous · Answer

okay!:)

pooja195 · Answer

$$\huge~x=\frac{ 3 \pm \sqrt{(-3)^2-4(2)(-2)} }{ 2(2)} $$
simplify whats in the square root but DO NOT square root it

anonymous · Answer

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