Question

A 98-N sack of grain is hoisted to a storage room 50 m above the ground floor of a grain elevator

a. How much work was required?

b. What is the potential energy of the sack of grain at this height?

c. The rope being used to lift the sack of grain breaks just as the sack reaches the storage room. What kinetic energy does the sack have just before it strikes the ground floor?

Answer 1

a.
W=F*h

Answer 2

Here
W=work
F=force
h=height

Answer 3

W=?

Answer 4

b.
P.E=w

Answer 5

This isn't helping me.

Answer 6

Ok. I m trying to help u!!

Answer 7

U know
Work=force*displacement
Right?

Answer 8

Weight of sack is=98N
Right?

Answer 9

So u need to spply a force of 98N to lift the sack of grain.

Answer 10

Now displacement =?

Answer 11

Here displacement = height=50m

Answer 12

So
W=?

Answer 13

Response plz!!