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A 98-N sack of grain is hoisted to a storage room 50 m above the ground floor of a grain elevator a. How much work was required? b. What is the potential energy of the sack of grain at this height? c. The rope being used to lift the sack of grain breaks just as the sack reaches the storage room. What kinetic energy does the sack have just before it strikes the ground floor?
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a. W=F*h
Here W=work F=force h=height
W=?
b. P.E=w
This isn't helping me.
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Ok. I m trying to help u!!
U know Work=force*displacement Right?
Weight of sack is=98N Right?
So u need to spply a force of 98N to lift the sack of grain.
Now displacement =?
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Here displacement = height=50m
So W=?
Response plz!!
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