The red light from a He-Ne (helium-neon) laser has a wavelength of 633 nm. What is the frequency of the light?
A. 4.7 × 10^14 Hz
B. 4.7 × 10^5 Hz
C. 190 Hz
D. 1.9 × 10^11 Hz
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OpenStudy (michele_laino):
it is simple, since we have to apply this formula:
\[\Large \lambda \nu = c\]
OpenStudy (anonymous):
okay!! what do we plug in? :/
OpenStudy (michele_laino):
here is the computation:
\[\Large \nu = \frac{c}{\lambda } = \frac{{3 \times {{10}^{10}}}}{{6.33 \times {{10}^{ - 7}}}}\]
OpenStudy (anonymous):
okay!! and so we get 4.739336493E16 ?
OpenStudy (michele_laino):
where I have used these values:
c=3*10^10 cm/sec
\lambda=633*10^-9 meters = 6.33*10^-7 meters=6.33*1^-5 cm
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OpenStudy (anonymous):
ahh okie!
OpenStudy (anonymous):
and so our solution is choice A?
OpenStudy (michele_laino):
please wait, I have made an error, here is the right computation:
\[\Large \nu = \frac{c}{\lambda } = \frac{{3 \times {{10}^{10}}}}{{6.33 \times {{10}^{ - 5}}}}\]
OpenStudy (anonymous):
ohh okay!! so we get 4.739336493E14?
so that is choice A still? :P
OpenStudy (michele_laino):
ok!
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