someone help me understand this :(
tangent of any angle of a right angled triangle = height of that triangle/base of that triangle
for your diagram height = 27500 base = 5000
yes i got that. i just dont understand the last step :( how did they get that answer?
im using that as an example for a question my test i just got so confused at the last part
on my**
That is where you take the inverse tangent function of that whole expression \[\large tan(x) = 5.5 \rightarrow x = tan^{-1}(5.5)\]
ohh okay. can i put the question from my test on here and ill walk through the steps and you tell me if im the right track or not?
It will work like that with all your trig functions If \(\large sin(x) = \text{something}\rightarrow x = \sin^{-1}(\text{something})\) If \(\large cos(x) = \text{something}\rightarrow x = \cos^{-1}(\text{something})\) If \(\large tan(x) = \text{something}\rightarrow x = \tan^{-1}(\text{something})\)
And yeah of course!
so i used sin for this one
Correct
and i got b
And you would be correct again :)
yes!! thank you so much :D
Not a problem! Good luck on the rest of your test :D
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