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OpenStudy (anonymous):
OpenStudy (anonymous):
tangent of any angle of a right angled triangle = height of that triangle/base of that triangle
OpenStudy (anonymous):
for your diagram height = 27500
base = 5000
OpenStudy (anonymous):
yes i got that. i just dont understand the last step :( how did they get that answer?
OpenStudy (anonymous):
im using that as an example for a question my test i just got so confused at the last part
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OpenStudy (anonymous):
on my**
OpenStudy (johnweldon1993):
That is where you take the inverse tangent function of that whole expression
\[\large tan(x) = 5.5 \rightarrow x = tan^{-1}(5.5)\]
OpenStudy (anonymous):
ohh okay. can i put the question from my test on here and ill walk through the steps and you tell me if im the right track or not?
OpenStudy (johnweldon1993):
It will work like that with all your trig functions
If \(\large sin(x) = \text{something}\rightarrow x = \sin^{-1}(\text{something})\)
If \(\large cos(x) = \text{something}\rightarrow x = \cos^{-1}(\text{something})\)
If \(\large tan(x) = \text{something}\rightarrow x = \tan^{-1}(\text{something})\)
OpenStudy (johnweldon1993):
And yeah of course!
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OpenStudy (anonymous):
OpenStudy (anonymous):
so i used sin for this one
OpenStudy (johnweldon1993):
Correct
OpenStudy (anonymous):
and i got b
OpenStudy (johnweldon1993):
And you would be correct again :)
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OpenStudy (anonymous):
yes!! thank you so much :D
OpenStudy (johnweldon1993):
Not a problem! Good luck on the rest of your test :D