Question

How can I find the exact value of:
sec[arctan(2)]

Answer 1

let theta = arctan(2)

this means that tan(theta) = 2 = 2/1

recall that tangent deals with opposite/adjacent, so because tan(theta) = 2/1, we know

Answer 2

are you able to find the length of the hypotenuse?

Answer 3

yes

Answer 4

the question is direct at @Tracy96

Answer 5

@jim_thompson5910 yep! I got it! So I gotta use Pythagorus, correct?

Answer 6

length^2+width^2=hypotenuse^ 2

Answer 7

correct @Tracy96

Answer 8

you have to use a^2 + b^2 = c^2

a = 1
b = 2
c = unknown for now

Answer 9

@henryli is correct too!!

Answer 10

corect

Answer 11

@jim_thompson5910 right, so hypotenuse would be sqrt(5) ?

Answer 12

yep

Answer 13

yes that is correct