Question

COuld someone please help! im tired and i want to go to bed! ill give medals and whatever you need!
A function is shown below:

f(x) = x3 + 3x^2 - x - 3

Part A: What are the factors of f(x)? Show your work.

Part B: What are the zeros of f(x)? Show your work.

Part C: What are the steps you would follow to graph f(x)? Describe the end behavior of the graph of f(x).

Answer 1

@dan815 @nincompoop please help im really sorry for bothering you but i need help

Answer 2

@saifoo.khan

Answer 3

@sammixboo

Answer 4

@Australopithecus

Answer 5

i am so sorry for tagging everyone but i really need help

Answer 6

@paki

Answer 7

-1 is a root because if u plug in -1 it goes to 0

Answer 8

so it could be a factor of f(x)

Answer 9

i am so sorry if i come off as really stupid i am pretty much fried from all the work iv been doing

Answer 10

@dan815

Answer 11

im so sorry for bothering you my brother just actually came home and helped me do it. i am really sorry for being a nuisance

Answer 12

okay soq

Answer 13

listen

Answer 14

a root means that there is a point when x= that root y=0

Answer 15

that means this polynomail must have a
(x-r) (ax^2+bx+c)
if r is the root term

Answer 16

now we say that -1 is a root so,
(x+1) is a factor of x3 + 3x^2 - x - 3

to see what the (ax^2+bx+c) part what we do is
x3 + 3x^2 - x - 3
----------------- = use syntetic division and see what this is
(x+1)

this must be the ax^2+bx+c part except you would have solved for a b and c part


Then you can see if you can continue to factor this (ax^2+bx+c)

and make (x-r) (ax^2+bx+c) = (x-r1) (x-r2)(x-r3) into this completely product ant root form, r1,r2,r3 are the roots
in this case r1=-1

(x-(-1))(x-r2)(x-r3) = (x+1)(x-r2)(x-r3)
you still have to find r2 and r3 not that isnt a square or cube on r2 and r3 that is an index.