Question

Simplify and identify the domain.
-5/5x + 15 times 2(x + 2)/x^2 - 4

Answer 1

to identify the domain,
we need to see at which points, the function is undefined
so the function is undefined at three points.
those points are -3,2 and -2
the function is defined and exists at all real numbers except these three.
thus the domain is all real numbers except -3,-2,2

Answer 2

hello Bananas1234 is it right??

Answer 3

I think everyone needs a mandatory course in latex or something. I can't read this.

Answer 4

rajat, you're right for -2,2, and -3 will make the denominator 0. assuming that this is the right equation.

Answer 5

idk what latex is. and i agree with the -2, 2 and -3 but what about the simplify part?

Answer 6

@UsukiDoll

Answer 7

factor both denominators, then cancel common terms

Answer 8

look at the denominators

Answer 9

the numbers at which the denominators become zero are the numbers that will be excluded from the domain

Answer 10

-5/5x + 15 times 2(x + 2)/x^2 - 4

\[\frac{-5}{5x+15} \times \frac{2(x+2)}{x^2-4}\]

Answer 11

if we can pull that 5 out on the first denominator and then make sure that \[x^2-4 = (x+2)(x-2) \]

omg latex come on. x^2-4 = (x+2)(x-2)

cancel out some of the terms... you should be able to cancel out 2 of them

Answer 12

sorry my end is bugged... need to refresh

Answer 13

\[\frac{-5}{5(x+3)} \times \frac{2(x+2)}{(x+2)(x-2)}\] do you see anything that needs to be canceled out?

Answer 14

the common terms are 5 and x+2... since I can see them on the numerator and denominator we can cancel it out.

Answer 15

\[\frac{-1}{(x+3)} \times \frac{2}{(x-2)}\] and since we're not dealing with addition, we can just multiply this through. \[\frac{-2}{(x+3)(x-2)}\]

Answer 16

Thanks