Question

Let line t be the line represented by 3x+4y = 5 and let line p be the line perpendicular to line t and containing the point (5,5). What is the x-coordinate of the point common to line t and line p?

Answer 1

First, arrange the linear equation into slope-intercept form \(\large y = mx + b \)

Answer 2

Two perpendicular lines are defined by their negative reciprocal slopes. Meaning that if the slope of the first line is, \(m = \large \frac{2}{5} \) then the slope of the other line perpendicular to it is \(m = \large - \frac{5}{2} \)

Answer 3

Slope is -3/4, next

Answer 4

Upon performing the first step, that is arranging the linear equation into slope-intercept form, you will be able to determine its slope, and then determine the slope of other line with coordinates (5, 5) since it is said to be perpendicular.

Answer 5

so, if the slope is \(m \large = -\frac{3}{4} \) then what it is its negative reciprocal?

Answer 6

this is the -ve reciprocal