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Mathematics 21 Online
OpenStudy (anonymous):

Assume the readings on thermometers are normally distributed with a mean of 0C and a standard deviation of 1.00C. Find the probability that a randomly selected thermometer reads between -2.24 and -1.38. The probability is =

OpenStudy (amistre64):

and your thoughts?

OpenStudy (amistre64):

we are given a low value, a high value, a mean, and a deviation what function have we used that has these for inputs?

OpenStudy (anonymous):

By trying to find the area to the left of z?

OpenStudy (anonymous):

INVNORM?

OpenStudy (amistre64):

we have covered this before, its may be useful to make notes ....

OpenStudy (anonymous):

I agree ugh sorry

OpenStudy (amistre64):

how do we find the area between high and low values? the inverse of this operation defines a z score, we already have z scores so the invnorm function isnt going to be useful to us.

OpenStudy (anonymous):

normalcdf?

OpenStudy (amistre64):

thats the one and how do we input the information?

OpenStudy (anonymous):

Annnd thats what I forgot :(

OpenStudy (amistre64):

try to recall, what would you say is the most reasonable ?

OpenStudy (anonymous):

normalcdf(-1.38,-2.24,0,1)

OpenStudy (amistre64):

good effort, 0,1 is in the right spots but low,high is off -2.24 is to the left of -1.38, since its less than -1.38

OpenStudy (amistre64):

inputs are in order: low, high, mean, deviation

OpenStudy (amistre64):

you can try it as high, low .. it might say you did an error tho :)

OpenStudy (anonymous):

Ok, I'll try now

OpenStudy (amistre64):

the wolf takes the syntax: P((-2.24-0)/1 <z< (-1.38-0/1)), for a mean of 0 and sd of 1 just in case we need a reference to compare with

OpenStudy (anonymous):

Ok, so I tried Normalcdf(-1.38,-2.24,0,1) and it didn't work

OpenStudy (amistre64):

now swap the high and low about Normalcdf(-2.24,-1.38,0,1) that should work out

OpenStudy (anonymous):

Ugh nope. Not that either... What am I doing wrong? Should it be Normalpdf?

OpenStudy (amistre64):

pdf isnt valid here. and i cant be sure that youve hit the buttons correctly :)

OpenStudy (amistre64):

assuming you eventually get the hang of it, it shold give you a solution similar to this http://www.wolframalpha.com/input/?i=P%28-2.24%3Cz%3C-1.38%29

OpenStudy (amistre64):

CDF means: cumulative distribution function we are finding the sum of the area between 2 points, is a cumulative sum so we use the CDF function

OpenStudy (anonymous):

So it would then be 0.07 for the probability? How can I get into Wolfram? (For free)

OpenStudy (amistre64):

PDF is a probability distribution function, and it relates to a single point ... ive never had a need to use the PDF function

OpenStudy (anonymous):

Or 0.071 I can't figure out the rounding..

OpenStudy (amistre64):

i use the wolf for free all the time ...

OpenStudy (amistre64):

what do you have to round to? what number of deies?

OpenStudy (amistre64):

** decies

OpenStudy (anonymous):

Hmmm for some reason it never lets me. Maybe I just don't know how to find what I am trying to input and look for I guess

OpenStudy (anonymous):

Four decimal places as needed

OpenStudy (amistre64):

the syntax can be daunting i agree. its taken me a few years to learn the little I have for it

OpenStudy (anonymous):

Ok figured it out on my ti83 and I got -.071247

OpenStudy (amistre64):

then 2 or 3 decies is not appropriate .. 07120 < 07124 < 07130 4 6 we are closer to 0712

OpenStudy (anonymous):

I make that into a positive right?

OpenStudy (amistre64):

the negative is bad lol ... ignore that sign

OpenStudy (amistre64):

most likely your high,low values are mixed around.

OpenStudy (anonymous):

Ok lol! Thank you!!!

OpenStudy (amistre64):

yep

OpenStudy (anonymous):

I have plenty more that I still have that I am still confused about so you'll probably see me on here quite a bit

OpenStudy (amistre64):

as long as you can recall what it is we need to use, and if im about, ill try to guide your efforts

OpenStudy (anonymous):

Thank you so much

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