Assume the readings on thermometers are normally distributed with a mean of 0C and a standard deviation of 1.00C. Find the probability that a randomly selected thermometer reads between -2.24 and -1.38. The probability is =
and your thoughts?
we are given a low value, a high value, a mean, and a deviation what function have we used that has these for inputs?
By trying to find the area to the left of z?
INVNORM?
we have covered this before, its may be useful to make notes ....
I agree ugh sorry
how do we find the area between high and low values? the inverse of this operation defines a z score, we already have z scores so the invnorm function isnt going to be useful to us.
normalcdf?
thats the one and how do we input the information?
Annnd thats what I forgot :(
try to recall, what would you say is the most reasonable ?
normalcdf(-1.38,-2.24,0,1)
good effort, 0,1 is in the right spots but low,high is off -2.24 is to the left of -1.38, since its less than -1.38
inputs are in order: low, high, mean, deviation
you can try it as high, low .. it might say you did an error tho :)
Ok, I'll try now
the wolf takes the syntax: P((-2.24-0)/1 <z< (-1.38-0/1)), for a mean of 0 and sd of 1 just in case we need a reference to compare with
Ok, so I tried Normalcdf(-1.38,-2.24,0,1) and it didn't work
now swap the high and low about Normalcdf(-2.24,-1.38,0,1) that should work out
Ugh nope. Not that either... What am I doing wrong? Should it be Normalpdf?
pdf isnt valid here. and i cant be sure that youve hit the buttons correctly :)
assuming you eventually get the hang of it, it shold give you a solution similar to this http://www.wolframalpha.com/input/?i=P%28-2.24%3Cz%3C-1.38%29
CDF means: cumulative distribution function we are finding the sum of the area between 2 points, is a cumulative sum so we use the CDF function
So it would then be 0.07 for the probability? How can I get into Wolfram? (For free)
PDF is a probability distribution function, and it relates to a single point ... ive never had a need to use the PDF function
Or 0.071 I can't figure out the rounding..
i use the wolf for free all the time ...
what do you have to round to? what number of deies?
** decies
Hmmm for some reason it never lets me. Maybe I just don't know how to find what I am trying to input and look for I guess
Four decimal places as needed
the syntax can be daunting i agree. its taken me a few years to learn the little I have for it
Ok figured it out on my ti83 and I got -.071247
then 2 or 3 decies is not appropriate .. 07120 < 07124 < 07130 4 6 we are closer to 0712
I make that into a positive right?
the negative is bad lol ... ignore that sign
most likely your high,low values are mixed around.
Ok lol! Thank you!!!
yep
I have plenty more that I still have that I am still confused about so you'll probably see me on here quite a bit
as long as you can recall what it is we need to use, and if im about, ill try to guide your efforts
Thank you so much
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