Geometry
20 Online
OpenStudy (anonymous):
What is the length of CD?
http://media.apexlearning.com/Images/201004/04/19ddb83b-92c7-4835-8ee0-d1c224289299.gif
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OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
Can please someone help me with this one?
ganeshie8 (ganeshie8):
the triangles are similar, simply set up a proportion and solve x
ganeshie8 (ganeshie8):
\[\large \dfrac{15-x}{x}=\dfrac{20}{5}\]
solve \(x\)
OpenStudy (anonymous):
oh ok thank you
so once I solve it then that will be the answer right?
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ganeshie8 (ganeshie8):
what do you get when you solve ?
OpenStudy (anonymous):
Wait let me solve it
ganeshie8 (ganeshie8):
okie
OpenStudy (anonymous):
I got 3.75. Is that right?
ganeshie8 (ganeshie8):
doesn't look correct
try again
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OpenStudy (anonymous):
Okay
OpenStudy (anonymous):
0.7?
ganeshie8 (ganeshie8):
\[\large \dfrac{15-x}{x}=\dfrac{20}{5} \]
canceling common factor 5 on right hand side fraction gives
\[\large \dfrac{15-x}{x}=\dfrac{4}{1}\]
yes ?
OpenStudy (anonymous):
Yes.
ganeshie8 (ganeshie8):
cross multiply and get
\[15-x = 4x\]
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ganeshie8 (ganeshie8):
add \(x\) both sides
\[15 = 5x\]
OpenStudy (anonymous):
Okay
OpenStudy (anonymous):
so its 3
ganeshie8 (ganeshie8):
divide \(5\) both sides
\[3=x\]
which is same as
\[x=3\]
OpenStudy (anonymous):
Got it, thank you so much :)
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ganeshie8 (ganeshie8):
yw