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Geometry 20 Online
OpenStudy (anonymous):

What is the length of CD? http://media.apexlearning.com/Images/201004/04/19ddb83b-92c7-4835-8ee0-d1c224289299.gif

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

Can please someone help me with this one?

ganeshie8 (ganeshie8):

the triangles are similar, simply set up a proportion and solve x

ganeshie8 (ganeshie8):

\[\large \dfrac{15-x}{x}=\dfrac{20}{5}\] solve \(x\)

OpenStudy (anonymous):

oh ok thank you so once I solve it then that will be the answer right?

ganeshie8 (ganeshie8):

what do you get when you solve ?

OpenStudy (anonymous):

Wait let me solve it

ganeshie8 (ganeshie8):

okie

OpenStudy (anonymous):

I got 3.75. Is that right?

ganeshie8 (ganeshie8):

doesn't look correct try again

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

0.7?

ganeshie8 (ganeshie8):

\[\large \dfrac{15-x}{x}=\dfrac{20}{5} \] canceling common factor 5 on right hand side fraction gives \[\large \dfrac{15-x}{x}=\dfrac{4}{1}\] yes ?

OpenStudy (anonymous):

Yes.

ganeshie8 (ganeshie8):

cross multiply and get \[15-x = 4x\]

ganeshie8 (ganeshie8):

add \(x\) both sides \[15 = 5x\]

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

so its 3

ganeshie8 (ganeshie8):

divide \(5\) both sides \[3=x\] which is same as \[x=3\]

OpenStudy (anonymous):

Got it, thank you so much :)

ganeshie8 (ganeshie8):

yw

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