Question

write the equation of the line that passes through (3,8) and is parallel to the line -3x+y=12. Write your answer in slope intercept form

Answer 1

Hi Welcome to Openstudy @mathsucks_0 :)

First thing you need to know is the slope intercept form: \(\sf y=mx+b\) where m is the slop and b is the y-intercept. Next thing you need to do is determine the slope of -x+y=12, do you know how to do it?

Answer 2

oops supposed to be ** -3x+y=12

Answer 3

For slope I got -2/-3.. is that correct?

Answer 4

Oh actually I was looking at the wrong problem! But I am not able to get the slope

Answer 5

let's see..

i'll change it to slope intercept form, which will be:
-3x+y=12
y=3x+12

m=3 and b=12

the intercept for this equation is 3.

Now, since the line that you are looking for is PARALLEL to the given equation, they will have the SAME slope. So plug m=3 in the equation y=mx+b, what will you get for this part ?

Answer 6

y=3x+b

Answer 7

right :)

Using your given point (3,8), we can now solve for the y-int or b in the equation.
Plug in x=3 and y=8, then solve for b

Answer 8

b=8/3?

Answer 9

y=3x+b
8=3(3) + b -> plug in the points
b= 8-3(3) -> evaluate to solve for b

what will you get?

Answer 10

-1

Answer 11

I see what I did wrong, I missed where you wrote to plug in for x

Answer 12

i'm glad that you are figuring out where you did wrong ^_^
that's a good habit for students!

anyway, we're almost done
so m=3, b= -1
y=mx+b, put the values of m and b in the equation and you'll get?

Answer 13

y=3x-1

Answer 14

and you're done ! :)

Answer 15

Thank you!

Answer 16

you're welcome