Question

without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.
y=4x^2-12x+12

A. 2 points in common; vertex below x-axis
B. no points in common; vertex above x-axis
C. 1 point in common; vertex on x-axis
D. 2 points in common; vertex above x-axis

Answer 1

@peachpi

Answer 2

Calculate the discriminant.

Answer 3

x^2 - x + 2 = 0
the discriminant is b²-4ac when you have ax²+bx+c
therefore, you have a=1, b=-1, c=2, and
b²-4ac = (-1)² - 4(1)(2) = 1 - 8 = -7

Answer 4

make since?

Answer 5

thats a exsample just to help you understand. here let me solve for your problem

Answer 6

Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.

y = 4x^2 - 12x + 12
y = 4(x² - 3x) + 12
y = 4(x² - 3x + 3/4) + 12 - 3
y = 4(x - 3/2)² + 9
vertex: (3/2, 9)

no points in common; vertex above x-axis

Answer 7

So your answer would be B

Answer 8

does this make since @yayah2001 ?

Answer 9

thank you, I understand a lot better now.

Answer 10

Np! :D