Question

Use factoring to find the zeros of each equation y=x2+2x-24
Answers:
A.4,6
B.4,-6
C.-4,-6
D.-4,6

Answer 1

B

Answer 2

if we can not give out direct answers that would be great! ... At least show it's really B for the equation \[y=x^2+2x-24\] notice that the middle term is 2 and the last term is -24 so we need to find what two numbers we need to produce a positive 2

Answer 3

all possible combinations of 24 are
1 24
24 1
12 2
2 12
8 3
3 8
4 6
6 4
thank goodness for multiple choice, so we can use the
4 6
6 4
combinations

Answer 4

since or equation patter is a + and - we need to figure out which number has to be negative and which number has to be positive in order to achieve 2x and - 24

Answer 5

*our equation pattern... sorry typing fast

\[y=x^2+2x-24\]

Answer 6

I think that -4 and 6 will be perfect.. because of 2 reasons..
we know that (-4)(6) = -24
and -4+6 = 2

so now by factoring

we have

\[y=(x-4)(x+6)\]

we can check using the FOIL method and it does come back to the original equation that we had earlier.

Answer 7

to find our 0's we can just let y be 0 and solve for x. I think you could handle it from here
0=(x-4)(x+6)

It's like trying to ask yourself what x value do I need for this to hold true.

Answer 8

@Caylahill do you want me to go further or can you handle 0=(x-4)(x+6) and find all x's ?

Answer 9

you can just use inspection and see that there are 2 x values that will make the equation 0