A pair of equations is shown below: y = 8x − 9 y = 4x − 1 Part A: Explain how you will solve the pair of equations by substitution or elimination. Show all the steps and write the solution. (5 points) Part B: If the two equations are graphed, at what point will the lines representing the two equations intersect? Explain your answer. (5 points)
@Trinity_haha
I have no clue ;-; Try tagging so of the mods and ambassadors.
@ambassadors
@nincompoop @Preetha @pooja195 @triciaal
k that's enough.. anyway for a we can just use substitution.
suppose we have two equations y=8x-9 and y=4x-1. If we subsitute y =4x-1 into the first equation, we obtain 4x-1=8x-9 we need all the variable terms on the left side of the equation and all of the constant terms on the right side of the equation. Therefore, subtract 8x from both sides and add one on both sides 4x-8x-1=8x-8x-9 -4x-1 = -9 -4x-1+1 = -9+1 -4x = -8 dividing -4 on both sides we obtain x = 2 -4x = -8 ----- ----- -4 -4 x = 2 now to check to see if we got the right answer we substitute x = 2 back into the original equations y=8x-9 and y=4x-1. y = 8(2) - 9 = 16-9 =7 y=4(2)-1 = 8-1 = 7 Both of our y values are 7 7 = 8x -9 7 = 16-9 7=7 7 = 4x-1 7=8-1 7=7 Since we have 7 on both sides when x = 2, we have the correct answer.
wow thank you
as for part B I think I have already done it.. when two equations intersect, they have a point in common If we let x = 0 1 2 for y=8x-9, we have x y =8x-9 0 -9 1 8-9 = -1 2 16-9 = 7 Similarly, for y =4x-1 x y =4x-1 0 -1 1 4-1 =3 2 8-1 = 7 both of these equations have the point (2,7) in common. So the two lines will meet at point (2,7) . I would draw on OS, but lately their drawing system has been going nuts.
okay thank you
thanks so much
:)
you can use what I typed on here xD!
yeah i am lol
you got more time, i will post the other question in a different post so you can earn snother medal
another medal*
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